4x^2+0.25x-1.125=0

Solution for 4x^2+0.25x-1.125=0 equation:

4x^2+0.25x-1.125=0

a = 4; b = 0.25; c = -1.125;
Δ = b2-4ac
Δ = 0.252-4·4·(-1.125)
Δ = 18.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.25)-\sqrt{18.0625}}{2*4}=\frac{-0.25-\sqrt{18.0625}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.25)+\sqrt{18.0625}}{2*4}=\frac{-0.25+\sqrt{18.0625}}{8}
$